Question:
Evaluate:
$\sqrt[3]{4096}$
Solution:
$\sqrt[3]{4096}$
By prime factorisation:
$4096=2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2$
$=(2 \times 2 \times 2) \times(2 \times 2 \times 2) \times(2 \times 2 \times 2) \times(2 \times 2 \times 2)$
$=2^{3} \times 2^{3} \times 2^{3} \times 2^{3}$
$\therefore \sqrt[3]{4096}=(2 \times 2 \times 2 \times 2)=16$
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