Evaluate:

$\sqrt[3]{4096}$

By prime factorisation:

$4096=2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2$

$=(2 \times 2 \times 2) \times(2 \times 2 \times 2) \times(2 \times 2 \times 2) \times(2 \times 2 \times 2)$

$=2^{3} \times 2^{3} \times 2^{3} \times 2^{3}$

$\therefore \sqrt[3]{4096}=(2 \times 2 \times 2 \times 2)=16$