Enthalpy of combustion of carbon to CO2 is –393.5 kJ mol–1.

Question:

Enthalpy of combustion of carbon to $\mathrm{CO}_{2}$ is $393.5 \mathrm{~kJ} \mathrm{~mol}^{-1}$. Calculate the heat released upon formation of $35.2 \mathrm{~g}$ of $\mathrm{CO}_{2}$ from carbon and dioxygen gas.

Solution:

Formation of CO2 from carbon and dioxygen gas can be represented as:

$\mathrm{C}_{(s)}+\mathrm{O}_{2(g)} \longrightarrow \mathrm{CO}_{2(g)}$

$\Delta_{f} H=-393.5 \mathrm{~kJ} \mathrm{~mol}^{-1}$

$(1$ mole $=44 \mathrm{~g})$

Heat released on formation of $44 \mathrm{~g} \mathrm{CO}_{2}=-393.5 \mathrm{~kJ} \mathrm{~mol}^{-1}$

$\therefore$ Heat released on formation of $35.2 \mathrm{~g} \mathrm{CO}_{2}$

$=\frac{-393.5 \mathrm{~kJ} \mathrm{~mol}^{-1}}{44 \mathrm{~g}} \times 35.2 \mathrm{~g}$

$=-314.8 \mathrm{~kJ} \mathrm{~mol}^{-1}$

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