Question:
Draw a square whose each side measures 4.8 cm.
Solution:
(i) Draw side $\mathrm{AB}=4.8 \mathrm{~cm}$.
(ii) From A, make an angle of $90^{\circ}$ and cut it at $4.8 \mathrm{~cm}$ and mark it point D.
(iii) From B, make an angle of $90^{\circ}$ and cut it at $4.8 \mathrm{~cm}$ and mark it point C.
(iv) Join C and D.
Thus, $\mathrm{ABCD}$ is the required square.