Question:
Draw a rectangle whose one side measures 8 cm and the length of each of whose diagonals is 10 cm.
Solution:
(i) Draw a side AB, equal to 8 cm.
(ii) With A as the centre, draw an arc of length 10 cm.
(iii) Draw $\angle \mathrm{ABX}=90^{\circ}$, which intersects the arc at $\mathrm{C}$.
(iv) Draw $\angle B A Y=90^{\circ}$.
(v) With C as the centre, draw an arc of length 8 cm.
(vi) Join CD.
Thus, ABCD is the required rectangle..png)