Divide the sum of

Question:

Divide 6x3y2z2 by 3x2yz.

Solution:

$\frac{6 x^{3} y^{2} z^{2}}{3 x^{2} y z}$

$=\frac{6 \times x \times x \times x \times y \times y \times z \times z}{3 \times x \times x \times y \times z}$

$=2 x^{(3-2)} y^{(2-1)} z^{(2-1)}$

$=2 x y z$

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