Divide the sum of

Question:

Divide the sum of $\frac{65}{12}$ and $\frac{8}{3}$ by their difference.

Solution:

$\left(\frac{65}{12}+\frac{8}{3}\right) \div\left(\frac{65}{12}-\frac{8}{3}\right)$

$=\left(\frac{65}{12}+\frac{32}{12}\right) \div\left(\frac{65}{12}-\frac{32}{12}\right)$

$=\left(\frac{97}{12}\right) \div\left(\frac{33}{12}\right)$

$=\frac{97}{12} \times \frac{12}{33}$

$=\frac{97}{33}$

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