Divide the following

$\frac{24 a^{3} b^{3}}{-8 a b}$

$=\frac{24 \times a \times a \times a \times b \times b \times b}{-8 \times a \times b}$

$=-3 a^{(3-1)} b^{(3-1)}$

$=-3 a^{2} b^{2}$