Question:
Divide 4500 into two parts such that 5% of the first part is equal to 10% of the second part.
Solution:
Let the first part be $\mathrm{x}$.
Let the second part be $(4500-\mathrm{x})$.
$\therefore 5 \%$ of $x=10 \%$ of $(4500-x)$
$\Rightarrow\left(\frac{5}{100}\right) x=\left(\frac{10}{100}\right)(4500-x)$
$\Rightarrow \frac{5 x}{100}=\frac{45000-10 x}{100}$
$\Rightarrow 5 x=45000-10 x \quad$ (by cancellation of same denominators from both the sides)
$\Rightarrow 5 x+10 x=45000$
$\Rightarrow 15 x=45000$
$\Rightarrow x=\frac{45000}{15}=3000$
Therefore, the first part is $3000 .$
Second part $=(4500-x)=(4500-3000)=1500$