Question:
Divide 184 into two parts such that one-third of one part may exceed one-seventh of another part by 8.
Solution:
Let the first part of 184 be $\mathrm{x}$.
Therefore, the other part will be $(184-\mathrm{x})$.
According to the question,
$\frac{1}{3} \mathrm{x}-\frac{1}{7}(184-\mathrm{x})=8$
or $\frac{7 \mathrm{x}-552+3 \mathrm{x}}{21}=8$
or $10 \mathrm{x}-552=168[$ After c ross multiplication $]$
or $10 \mathrm{x}=168+552$
or $\mathrm{x}=\frac{720}{10}=72$
Thus, the parts of 184 are 72 and $112(184-72=112)$.