Question:
Divide:
(i) $16 \sqrt{6}$ by $4 \sqrt{2}$
(ii) $12 \sqrt{5}$ by $4 \sqrt{3}$
(iii) $18 \sqrt{21}$ by $6 \sqrt{7}$
Solution:
(i) $\frac{16 \sqrt{6}}{4 \sqrt{2}}=\frac{16 \sqrt{2} \sqrt{3}}{4 \sqrt{2}}=4 \sqrt{3}$
(ii) $\frac{12 \sqrt{15}}{4 \sqrt{3}}=\frac{12 \sqrt{5} \times \sqrt{3}}{4 \sqrt{3}}=3 \sqrt{5}$
(iii) $\frac{18 \sqrt{21}}{6 \sqrt{7}}=\frac{18 \sqrt{7} \sqrt{3}}{6 \sqrt{7}}=3 \sqrt{3}$
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