Question:
Determine graphically the vertices of the triangle, the equations of whose sides are given below :
(i) $2 y-x=8,5 y-x=14$ and $y-2 x=1$
(ii) $y=x, y=0$ and $3 x+3 y=10$
Solution:
(i) Draw the 3 lines as given by equations
By taking x=1 = 1 cm on x−axis
And y =1=1cm on y−axis
$\frac{y}{4}-\frac{x}{8}=1$
$\frac{y}{2.8}-\frac{x}{14}=1$
$\frac{y}{1}-\frac{x}{0.5}=1$
Clearly from graph points of intersection three lines are
(−4,2) , (1,3), (2,5)
(ii) Draw the 3 lines as given by equations
By taking x=1 = 1 cm on x−axis
And y =1=1cm on y−axis
$y=0$
$y=x$
$\frac{y}{10 / 3}+\frac{x}{10 / 3}=1$
