Question:
Curved surface area of a right circular cylinder is $4.4 \mathrm{~m}^{2}$. If the radius of the base of the cylinder is $0.7 \mathrm{~m}$. Find its height. (Take $\pi=3.14$ )
Solution:
Given that
Radius of the base of the cylinder (r) = 0.7 m
Curved surface area of cylinder (C.S.A) $=4.4 \mathrm{~m}^{2}$
Let the height of the cylinder be h
The curved surface area of a cylinder is given by: 2πrh
$2 \pi \mathrm{rh}=4.4 \mathrm{~m}^{2}$
$2 * 3.14^{*} 0.7^{*} \mathrm{~h}=4.4 \mathrm{~m}^{2}$
h = 4.4 ÷ 2 ∗ 3.14 ∗ 0.7
= 1 m
Therefore the height of the cylinder is 1 m.