Question:
Cube of $\frac{-1}{2}$ is
(a) $\frac{1}{8}$
(b) $\frac{1}{16}$
(c) $-\frac{1}{8}$
(d) $\frac{-1}{16}$
Solution:
(c) -1/8
The cube of a number is the number raised to the power of 3. Hence the cube of −1/2 is
$\frac{(-1)^{3}}{2^{3}} \quad \cdots\left((a / b)^{n}=\left(a^{n}\right) /\left(b^{n}\right)\right.$
$-\frac{1}{8}$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.