Question.
Convert into mole.
(a) 12 g of oxygen gas
(b) 20 g of water
(c) 22 g of carbon dioxide
Convert into mole.
(a) 12 g of oxygen gas
(b) 20 g of water
(c) 22 g of carbon dioxide
Solution:
(a) $32 \mathrm{~g}$ of oxygen gas $=1$ mole
Then, $12 \mathrm{~g}$ of oxygen gas $=\frac{12}{32}$
$=0.375 \mathrm{~mole}$
(b) $18 \mathrm{~g}$ of water $=1 \mathrm{~mole}$
Then, $20 \mathrm{~g}$ of water $=\frac{18}{20}$
$=1.11$ moles (approx)
(c) $44 \mathrm{~g}$ of carbon dioxide $=1$ mole
Then, $22 \mathrm{~g}$ of carbon dioxide $=\frac{22}{44}$
$=0.5$ mole
(a) $32 \mathrm{~g}$ of oxygen gas $=1$ mole
Then, $12 \mathrm{~g}$ of oxygen gas $=\frac{12}{32}$
$=0.375 \mathrm{~mole}$
(b) $18 \mathrm{~g}$ of water $=1 \mathrm{~mole}$
Then, $20 \mathrm{~g}$ of water $=\frac{18}{20}$
$=1.11$ moles (approx)
(c) $44 \mathrm{~g}$ of carbon dioxide $=1$ mole
Then, $22 \mathrm{~g}$ of carbon dioxide $=\frac{22}{44}$
$=0.5$ mole