Question:
Construct a rhombus the lengths of whose diagonals are 6 cm and 8 cm.
Solution:
We know that the diagonals of a rhombus bisect each other.
Steps of construction:
Step 1: Draw AC= 6cm
Step 2:Draw a perpendicular bisector(XY) of AC, which bisects AC at O.
Step 3: $O B=\frac{1}{2}(8) \mathrm{cm}$
$O B=4 \mathrm{~cm}$
and $O D=\frac{1}{2}(8) \mathrm{cm}$
$O D=4 \mathrm{~cm}$
Draw an arc of length 4 cm on OX and name that point as B.
Draw an arc of length 4 cm on OY and name that point as D.
Step 4 : Join AB, BC, CD and AD.
Thus, ABCD is the required rhombus, as shown in the figure.