Construct a quadrilateral XYZW in which XY = 5 cm,

Question:

Construct a quadrilateral XYZW in which XY = 5 cm, YZ = 6 cm, ZW = 7 cm, WX = 3 cm and XZ = 9 cm.

Solution:

Steps of construction:

Step I : Draw XZ $=9 \mathrm{~cm}$

Step II : With X as the centre and radius $5 \mathrm{~cm}$, draw an arc above XZ.

Step III : With Z as the centre and radius $6 \mathrm{~cm}$, draw an arc to intersect the arc drawn in Step II at Y above XZ.

Step IV : With Z as the centre and radius $7 \mathrm{~cm}$, draw an arc below XZ.

Step V: With X as the centre and radius $3 \mathrm{~cm}$, draw an arc to intersect the arc drawn in Step IV at W below XZ.

Step VI : Join XY, YZ, ZW and XW.

The quadrilateral WXYZ so obtained is the required quadrilateral.

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