Construct a quadrilateral PQRS in which PQ = 6 cm,

Steps of construction:

Step 1: Draw $Q R=5.6 \mathrm{~cm}$

Step 2: Make $\angle Q=45^{\circ}$ and $\angle R=90^{\circ}$

Step 3: With $Q$ as the centre, draw an arc of $6 \mathrm{~cm}$. Name that point as $P$.

Step 4: With $R$ as the centre, draw an arc of $2.7 \mathrm{~cm}$. Name that point as $S$.

Step 6: Join $P$ and $S$.

Then, $P Q R S$ is the required quadrilateral.