Construct a quadrilateral PQRS in which PQ = 5.4 cm,

Steps of construction:

Step 1: Draw $\mathrm{PQ}=5.4 \mathrm{~cm}$.

Step 2: With $P$ as the centre and radius equal to $4 \mathrm{~cm}$, draw an arc.

Step 3: With $Q$ as the centre and radius equal to $4.6 \mathrm{~cm}$, draw another arc, cutting the previous arc at $R$.

Step 4: Join QR.

Step 5: With P as the centre and radius equal to $3.5 \mathrm{~cm}$, draw an arc.

Step 6: With $R$ as the centre and radius equal to $4.3 \mathrm{~cm}$, draw another arc, cutting the previous arc at $S$.

Step 7: Join $P S$ and $R S$.

Thus, PQRS is the required quadrilateral.