Question:
Construct a quadrilateral ABCD in which BC = 7.5 cm, AC = AD = 6 cm, CD = 5 cm and BD = 10 cm.
Solution:
Steps of construction:
Step I: Draw AC $=6 \mathrm{~cm} .$
Step II : With A as the centre and radius $6 \mathrm{~cm}$, draw an arc.
Step III : With C as the centre and radius $5 \mathrm{~cm}$, draw an arc to intersect the arc drawn in Step II at D.
Step IV : With D as the centre and radius $10 \mathrm{~cm}$, draw an arc on the other side of the line segment AC.
Step V : With C as the centre and radius $7.5 \mathrm{~cm}$, draw an arc to intersect the arc drawn in Step IV at B.
Step VI : Join BA, DA, BC and CD to obtained the required quadrilateral.