Construct a quadrilateral ABCD in which AB = 3.8 cm,

Question:

Construct a quadrilateral ABCD in which AB = 3.8 cm, BC = 3.4 cm, CD = 4.5 cm, AD = 5 cm and ∠B = 80°.

Solution:

Steps of construction:

Step I: Draw $\mathrm{AB}=3.8 \mathrm{~cm}$.

Step II : Construct $\angle \mathrm{ABC}=80^{\circ}$.

Step III : With B as the centre and radius $3.4 \mathrm{~cm}$, cut off BC $=3.4 \mathrm{~cm}$.

Step IV : With C as the centre and radius $4.5 \mathrm{~cm}$, draw an arc.

Step V : With A as the centre and radius $5.3 \mathrm{~cm}$, draw an arc to intersect the arc drawn in Step IV at D.

Step VI: Join $A D$, BC and CD to obtained the required quadrilateral.

Leave a comment