Construct a quadrilateral ABCD in which AB = 3.5 cm,

Steps of construction:

Step 1: Draw $B C=5 \mathrm{~cm}$

Step 2: Make $\angle B=125^{\circ}$ and $\angle C=60^{\circ}$

Step 3: With $B$ as the centre, draw an arc of $3.5 \mathrm{~cm}$. Name that point as $A$.

Step 4: With $C$ as the centre, draw an arc of $4.6 \mathrm{~cm}$. Name that point as $D$.

Step 5: Join $A$ and $D$.

Then, $A B C D$ is the required quadrilateral.