Question:
construct a quadrilateral ABCD in which AB =3.4 cm, CD = 3 cm, DA = 5.7 cm, AC = 8 cm and BD = 4 cm.
Solution:
Steps of construction:
Step 1: Draw $A B=3.4 \mathrm{~cm} .$
Step 2: With $B$ as the centre and radius equal to $4 \mathrm{~cm}$, draw an arc.
Step 3: With $A$ as the centre and radius equal to $5.7 \mathrm{~cm}$, draw another arc, cutting the previous arc at $D$.
Step 4: Join $B D$ and $A D$.
Step 5: With $A$ as the centre and radius equal to $8 \mathrm{~cm}$, draw an arc.
Step 6: With $D$ as the centre and radius equal to $3 \mathrm{~cm}$, draw another arc, cutting the previous arc at $C$.
Step 7: Join $A C, C D$ and $B C$.
Thus, ABCD is the required quadrilateral.