Construct a quadrilateral ABCD in which AB = 2.9 cm,

Steps of construction:

Step 1: Draw $A B=2.9 \mathrm{~cm}$

Step 2: Make $\angle A=70^{\circ}$

Step 3: With $A$ as the centre, draw an arc of $3.4 \mathrm{~cm}$. Name that point as $D$.

Step 4: With $D$ as the centre, draw an arc of $2.7 \mathrm{~cm}$.

Step 5: With $B$ as the centre, draw an arc of $3.2 \mathrm{~cm}$, cutting the previous arc at $C$.

Step 6: Join $C D$ and $B C$.

Then, $A B C D$ is the required quadrilateral.