Question:
Construct a quadrilateral ABCD in which AB = 2.8 cm, BC = 3.1 cm, CD = 2.6 cm, and DA = 3.3 cm and ∠A = 60°.
Solution:
Steps of construction :
Step I : Draw $\mathrm{AB}=2.8 \mathrm{~cm}$.
Step II : Construct $\angle \mathrm{BAD}=60^{\circ}$.
Step III : With A as the centre and radius $3.3 \mathrm{~cm}$, cut off $\mathrm{AD}=3.3 \mathrm{~cm}$.
Step IV: With D as the centre and radius $2.6 \mathrm{~cm}$, draw an arc.
Step V : With B as the centre and radius $3.1 \mathrm{~cm}$, draw an arc to intersect the arc drawn in Step IV at C.
Step VI : Join BC and CD to obtained the required quadrilateral.
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