Construct a parallelogram PQRS such that PQ = 5.2 cm,

In a parallelogram opposite sides are equal. Thus, we have to construct a quadrilateral PQRS in which $\mathrm{PQ}=5.2 \mathrm{~cm}, \mathrm{PR}=6.8 \mathrm{~cm}$ and $\mathrm{QS}=8.2 \mathrm{~cm} .$

Steps of construction:

Step I: Draw QS $=8.2 \mathrm{~cm}$

Step II : With Q as the centre and radius $5.2 \mathrm{~cm}$, draw an arc.

Step III : With S as the centre and radius $5.2 \mathrm{~cm}$, draw an arc to intersect the arc drawn in Step II at C.

Step IV : With P as the centre and radius $6.8 \mathrm{~cm} .$

Step V: With Q as the centre and radius $5.2 \mathrm{~cm}$, draw an arc to intersect the arc drawn in Step IV at A.

Step VI : Join QR, QP, PS and SR.

The quadrilateral PQRS so obtained is the required quadrilateral.