Question:
Construct a parallelogram ABCD in which AB = 5.2 cm, BC = 4.7 cm and AC = 7.6 cm.
Solution:
Steps of construction:
Step 1: Draw $A B=5.2 \mathrm{~cm}$
Step 2: With $B$ as the centre, draw an $\operatorname{arc}$ of $4.7 \mathrm{~cm}$.
Step 3: With $A$ as the centre, draw another arc of $7.6 \mathrm{~cm}$, cutting the previous arc at $C$.
Step 4: Join $A$ and $C$.
Step 5: We know that the opposite sides of a parallelogram are equal. Thus, with $C$ as the centre, draw an arc of $5.2 \mathrm{~cm}$.
Step 6: With $A$ as the centre, draw another arc of $4.7 \mathrm{~cm}$, cutting the previous arc at $D$.
Step 7: Join $C D$ and $A D$.
Then, ABCD is the required parallelogram.