Question:
Consider titration of $\mathrm{NaOH}$ solution versus $1.25 \mathrm{M}$ oxalic acid solution. At the end point following burette readings were obtained.
(i) $4.5 \mathrm{~mL}$
(ii) $4.5 \mathrm{~mL}$
(iii) $4.4 \mathrm{~mL}$
(iv) $4.4 \mathrm{~mL}$
(v) $4.4 \mathrm{~mL}$
If the volume of oxalic acid taken was $10.0 \mathrm{~mL}$ then the molarity of the $\mathrm{NaOH}$ solution is________
M. (Rounded-off to the nearest integer)
Solution:
$\mathrm{V}_{\mathrm{NaOH}}=4.4 \mathrm{ml}$
eq. of $\mathrm{NaOH}=$ eq. of $\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}$
or, $\mathrm{M} \times 4.4 \times 1=1.25 \times 10 \times 2$
or, $\mathrm{M}=5.68 \mathrm{M}$
$\therefore$ Nearest integer answer is 6