Consider the following reversible chemical reactions:

$\mathrm{K}_{1} \mathrm{~K}_{2}=\frac{1}{3}$

$\mathrm{K}_{2}=\mathrm{K}_{1}{ }^{3}$

$\mathrm{K}_{2}=\mathrm{K}_{1}^{-3}$

$\mathrm{K}_{1} \mathrm{~K}_{2}=3$