Question:
Consider an infinitely long wire carrying a current I (t ), with dI dt =λ= constant. Find the current produced in the rectangular loop of wire ABCD if its resistance is R.
Solution:
The width of the strip is dr and the length is l which is inside the rectangular box at a distance r from the surface of the current-carrying conductor. The magnetic field across the strip length is given as
l = B(r) = μoI/2πr
B(r) is perpendicular to the paper upward.
Flux in the strip = ϕ = μoIl/2π [loger]
ε=-dϕ/dt
Therefore, I = μoλl/2πR loge x/xo
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.