Question:
Consider a uniform wire of mass $\mathrm{M}$ and length $\mathrm{L}$. It is bent into a
semicircle. Its moment of inertia about a line perpendicular to the plane of the wire passing through the centre is :
Correct Option: , 3
Solution:
(3)
$\pi \mathrm{r}=\mathrm{L} \Rightarrow \mathrm{r}=\frac{\mathrm{L}}{\pi}$
$\mathrm{I}=\mathrm{Mr}^{2}=\frac{\mathrm{ML}^{2}}{\pi^{2}}$
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