Question:
Consider a pair of identical pendulums, which oscillate with equal amplitude independently such that when one pendulum is at its extreme position making an angle of 2o to the right with the vertical, the other pendulum makes an angle of 1o to the left of the vertical. What is the phase difference between the pendulums?
Solution:
θ1 = θ0 sin (wt + δ1)
θ2 = θ0 sin (wt + δ2)
for first, θ = 2o
for second, θ = -1o
δ1 – δ2 = 120o