Question:
Common factor of 17abc, 34ab2, 51a2b is
(a) 17abc
(b) 17ab
(c) 17ac
(d) 17a2b2c
Solution:
(b) 17ab
The given factors can be written in expanded form as,
17abc = 17 × a × b × c
34ab2 = 2 × 17 × a × b × b
51a2b = 3 × 17 × a × a × b
So, common factors in the above is 17 × a × b
= 17ab
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