Choose the correct answer of the following question:
The angle of depression of a car parked on the road from the top of a 150-m-high tower is 30°. The distance of the car from the tower is
(a) $50 \sqrt{3} \mathrm{~m}$
(b) $150 \sqrt{3} \mathrm{~m}$
(c) $150 \sqrt{2} \mathrm{~m}$
(d) $75 \mathrm{~m}$
Let AB be the tower and point C be the position of the car.
We have,
$\mathrm{AB}=150 \mathrm{~m}$ and $\angle \mathrm{ACB}=30^{\circ}$
In $\Delta \mathrm{ABC}$,
$\tan 30^{\circ}=\frac{\mathrm{AB}}{\mathrm{BC}}$
$\Rightarrow \frac{1}{\sqrt{3}}=\frac{150}{\mathrm{BC}}$
$\therefore \mathrm{BC}=150 \sqrt{3} \mathrm{~m}$
Hence, the correct answer is option (b)
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