Question:
Calculate the value of mean free path $(\lambda)$ for oxygen molecules at temperature $27^{\circ} \mathrm{C}$ and pressure $1.01 \times 10^{5} \mathrm{~Pa}$. Assume the molecular diameter $0.3 \mathrm{~nm}$ and the gas is ideal. $\left(\mathrm{k}=1.38 \times 10^{-23} \mathrm{JK}^{-1}\right)$
$\left(\mathrm{k}=1.38 \times 10^{-23} \mathrm{JK}^{-1}\right)$
Correct Option: , 4
Solution:
$\lambda=\frac{\mathrm{RT}}{\sqrt{2} \pi \mathrm{d}^{2} \mathrm{~N}_{\mathrm{A}} \mathrm{P}}$
$\lambda=102 \mathrm{~nm}$