Question:
Calculate the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar.
$\left(\mathrm{R}=0.083\right.$ bar $\left.\mathrm{dm}^{3} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right)$
Solution:
Given,
n = 4.0 mol
V = 5 dm3
p = 3.32 bar
R = 0.083 bar dm3 K–1 mol–1
The temperature (T) can be calculated using the ideal gas equation as:
$p V=n \mathrm{R} T$
$\Rightarrow T=\frac{p V}{n \mathrm{R}}$
$=\frac{3.32 \times 5}{4 \times 0.083}$
$=50 \mathrm{~K}$
Hence, the required temperature is 50 K.