Calculate the potential of hydrogen electrode in contact

For hydrogen electrode, $\mathrm{H}^{+}+\mathrm{e}^{-} \longrightarrow \frac{1}{2} \mathrm{H}_{2}$, it is given that $\mathrm{pH}=10$

∴[H+] = 10−10 M

Now, using Nernst equation:

=  

= −0.0591 log 1010

= −0.591 V