Question:
Calculate the amount of charge on capacitor of $4 \mu \mathrm{F}$. The internal resistance of battery is $1 \Omega$ :
Correct Option: 1
Solution:
On simplifying circuit we get
No current in upper wire.
$\therefore \quad \mathrm{V}_{\mathrm{AB}}=\frac{5}{4+1} \times 4=4 \mathrm{v}$
$\therefore \quad \theta=\left(\mathrm{C}_{\mathrm{eq}}\right) \mathrm{v}$
$\Rightarrow 2 \times 4=8 \mu \mathrm{C}$
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