Question:
By what number should we multiply $\frac{-1}{6}$ so that the product may be $\frac{-23}{9} ?$
Solution:
Let the number $b e \mathrm{x}$.
$\therefore \mathrm{x} \times \frac{-1}{6}=\frac{-23}{9}$
$\begin{aligned} \mathrm{x} &=\frac{-23}{9} \div \frac{-1}{6} \\ \mathrm{x} &=\frac{-23}{9} \times \frac{6}{-1}=\frac{46}{3} \end{aligned}$
Therefore, the other number is $\frac{46}{3}$.