Question:
By what number should $\frac{-33}{8}$ be divided to get $\frac{-11}{2} ?$
Solution:
Let the number be $\mathrm{x}$.
Now,
$\frac{-33}{8} \div \mathrm{x}=\frac{-11}{2}$
$\Rightarrow \frac{-33}{8} \times \frac{1}{\mathrm{x}}=\frac{-11}{2}$
$\Rightarrow \frac{1}{\mathrm{x}}=\frac{-11}{2} \div \frac{-33}{8}$
$\Rightarrow \frac{1}{\mathrm{x}}=\frac{-11}{2} \times \frac{8}{-33}$
$\Rightarrow \frac{1}{\mathrm{x}}=\frac{88}{66}$
$\Rightarrow \frac{1}{\mathrm{x}}=\frac{4}{3}$
$\Rightarrow \mathrm{x}=\frac{3}{4}$ (Reciprocal of $\frac{4}{3}$ )