By what number should

Question:

By what number should $\frac{-33}{8}$ be divided to get $\frac{-11}{2} ?$

Solution:

Let the number be $\mathrm{x}$.

Now,

$\frac{-33}{8} \div \mathrm{x}=\frac{-11}{2}$

$\Rightarrow \frac{-33}{8} \times \frac{1}{\mathrm{x}}=\frac{-11}{2}$

$\Rightarrow \frac{1}{\mathrm{x}}=\frac{-11}{2} \div \frac{-33}{8}$

$\Rightarrow \frac{1}{\mathrm{x}}=\frac{-11}{2} \times \frac{8}{-33}$

$\Rightarrow \frac{1}{\mathrm{x}}=\frac{88}{66}$

$\Rightarrow \frac{1}{\mathrm{x}}=\frac{4}{3}$

$\Rightarrow \mathrm{x}=\frac{3}{4}$            (Reciprocal of $\frac{4}{3}$ )

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