Question:
At very high frequencies, the effective impendance
of the given circuit will be $\Omega .$
Solution:
$\mathrm{X}_{\mathrm{L}}=2 \pi \mathrm{fL}$
$\mathrm{f}$ is very large
$\therefore \mathrm{X}_{\mathrm{L}}$ is very large hence open circuit.
$X_{C}=\frac{1}{2 \pi f C}$
$\mathrm{f}$ is very large.
$\therefore \mathrm{X}_{\mathrm{C}}$ is very small, hence short circuit.
Final circuit
$Z_{\mathrm{cq}}=1+\frac{2 \times 2}{2+2}=2$
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