At 3:40, the hour and minute hands of a clock are inclined at
(a) $\frac{2 \pi^{c}}{3}$
(b) $\frac{7 \pi^{\mathrm{c}}}{12}$
(C) $\frac{13 \pi_{\mathrm{c}}}{18}$
(d) $\frac{13 \pi_{c}}{4}$
(C) $\frac{13 \pi_{\mathrm{c}}}{18}$
We know that the hour hand of a clock completes one rotation in 12 hours.
∴ Angle traced by the hour hand in 12 hours = 360°
Now,
Angle traced by the hour hand in 3 hours 40 minutes, i.e., $\frac{11}{3}=\left(\frac{360}{12} \times \frac{11}{3}\right)^{\circ}=110^{\circ}$
We also know that the minute hand of a clock completes one rotation in 60 minutes.
∴ Angle traced by the minute hand in 60 minutes = 360°
Now,
Angle traced by the minute hand in 40 minutes $=\left(\frac{360}{60} \times 40\right)^{\circ}=240^{\circ}$
∴ Required angle between two hands =
And,
Value of the angle (in radians) between the two hands of the clock $=\left(130 \times \frac{\pi}{180}\right)^{c}=\left(\frac{13 \pi}{18}\right)^{c}=\frac{13 \pi^{c}}{18}$