Question:
Assume that there is no repulsive force between the electrons in an atom but the force between positive and negative charges is given by Coulomb’s law as usual. Under such circumstances, calculate the ground state energy of a He-atom.
Solution:
For He nucleus, Z = 2 and in-ground state n = 1
Therefore, En = -13.6 Z2/n2 eV = -54.4 eV
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.