Question:
An object is located at $2 \mathrm{~km}$ beneath the surface of the water. If the fractional compression $\frac{\Delta \mathrm{V}}{\mathrm{V}}$ is $1.36 \%$, the ratio of hydraulic stress to the corresponding hydraulic strain will be [Given : density of water is $1000 \mathrm{~kg} \mathrm{~m}^{-3}$ and $\mathrm{g}=9.8 \mathrm{~ms}^{-2} .$ ] (1) $1.96 \backslash$ times $10^{\wedge}\{7\} \backslash$ mathrm $\{\mathrm{Nm}\}^{\wedge}\{-2\} \$$
Correct Option: , 4
Solution:
(4)
$P=h \rho g$
$\beta=\frac{p}{\frac{\Delta V}{V}}=\frac{2 \times 10^{3} \times 10^{3} \times 9.8}{1.36 \times 10^{-2}}$
$=1.44 \times 10^{9} \mathrm{~N} / \mathrm{m}^{2}$