Question:
An irrational number between $\sqrt{2}$ and $\sqrt{3}$ is
(a) $(\sqrt{2}+\sqrt{3})$
(b) $\sqrt{2} \times \sqrt{3}$
(c) $5^{1 / 4}$
(d) $6^{1 / 4}$
Solution:
(d) $6^{1 / 4}$
An irrational number between $\sqrt{2}$ and $\sqrt{3}$ :
$\sqrt{\sqrt{2} \times \sqrt{3}}=6^{\frac{1}{4}}$