Question:
An inductor $(\mathrm{L}=0.03 \mathrm{H})$ and a resistor $(\mathrm{R}=0.15 \mathrm{k} \Omega)$ are connected in series to a battery of $15 \mathrm{~V}$ EMF in a circuit shown below. The key $\mathrm{K}_{1}$ has been kept closed for a long time. Then at $\mathrm{t}=0, \mathrm{~K}_{1}$ is opened and key $\mathrm{K}_{2}$ is closed simultaneously. At $\mathrm{t}=1 \mathrm{~ms}$, the current in the circuit will be $\left(\mathrm{e}^{5} \cong 150\right):-$
Correct Option: , 2
Solution: