An express train takes 1 hour less than a passenger train to travel 132 km between Mysore and Banglore.
An express train takes 1 hour less than a passenger train to travel 132 km between Mysore and Banglore. If the average speed of the express train is 11 km/hr more than that of the passenger train, from the quadratic equation to find the average speed of express train.
Now let us assume that the speed of the express train be ‘x’ km/hr. Therefore according to the question speed of the passenger train will be ‘x −11’ km/hr. Now we know that the total distance travelled by both the trains was 132 km.
We also know that
So the time taken by express train would be $\left(\frac{132}{x}\right)$ hr and the time taken by the passenger train would be $\left(\frac{132}{x-11}\right)$ hr. Now, we also know that the express train took 1 hr less than the passenger train to travel the whole distance.
Therefore, we have
$\left(\frac{132}{x}\right)=\left(\frac{132}{x-11}\right)-1$
$\left(\frac{132}{x-11}\right)-\left(\frac{132}{x}\right)=1$
$\left(\frac{132 x-132(x-11)}{x^{2}-11 x}\right)=1$
$x^{2}-11 x-1452=0$
Therefore, this is the required equation.