Question.
An army contingent of 616 members is to march behind an army band of 32 members in a parade. The two groups are to march in the same number of columns. What is the maximum number of columns in which they can march?
An army contingent of 616 members is to march behind an army band of 32 members in a parade. The two groups are to march in the same number of columns. What is the maximum number of columns in which they can march?
Solution:
616 and 32
$616=32 \times 19+8$
$32=4 \times 8$
$\operatorname{HCF}$ of $(616,32)=8$
616 and 32
$616=32 \times 19+8$
$32=4 \times 8$
$\operatorname{HCF}$ of $(616,32)=8$