Question:
An amplitude modulated wave is as shown in the figure. Calculate
(i) the percentage modulation
(ii) peak carrier voltage and
(iii) peak value of information voltage
Solution:
Maximum voltage, Vmax = 100/2 = 50 V
Minimum voltage, Vmin = 20/2 = 10 V
(i) Percentage modulation = 66.67%
(ii) Peak carrier voltage, Vc = 30 V
(iii) Peak value of information voltage = 20 V
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