An A.P. consists of 60 terms. If the first and the last terms be 7 and 125 respectively,

Given;

$a=7, n=60, l=125$

$l=a+(n-1) d$

$\Rightarrow 125=7+(60-1) d$

$\Rightarrow 125=7+59 d$

$\Rightarrow 118=59 d$

$\Rightarrow 2=d$

$a_{32}=a+(32-1) d$

$=a+31 d$

$=7+31 \times 2$

$=7+62$

$=69$