Question:
Among the compounds $A$ and $B$ with molecular formula $\mathrm{C}_{9} \mathrm{H}_{18} \mathrm{O}_{3}, A$ is having higher boiling point the $B$. The possible structures of $A$ and $B$ are:
Correct Option: 1
Solution:
In (A), $-\mathrm{OH}$ group is present, so inter-molecular H-bonding is possible while in (B), due to methoxy group there is no possibility of Inter-molecular H-bonding. So $\mathrm{A}$ is having higher boiling point than B.
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.